More questions on this topic
More questions on this topic ( 15 Questions)
A patient’s umbilical cord prolapses during labor.
The nurse should place her in which position? (Select all that apply.).
The nurse should place the patient in knee-chest or Trendelenburg position to relieve the pressure of the fetal presenting part on the prolapsed cord and improve fetal oxygenation. These positions also allow gravity to help keep the cord in the uterus and prevent further descent.
The nurse should place the patient in knee-chest or Trendelenburg position to relieve the pressure of the fetal presenting part on the prolapsed cord and improve fetal oxygenation. These positions also allow gravity to help keep the cord in the uterus and prevent further descent.
Supine position can worsen cord compression and compromise fetal blood flow
Lithotomy position can also increase cord descent and reduce fetal perfusion
Sims position can cause cord prolapse if the membranes are intact or rupture spontaneously.
The correct answer is choice A and B. The nurse should place the patient in knee-chest or Trendelenburg position to relieve the pressure of the fetal presenting part on the prolapsed cord and improve fetal oxygenation. These positions also allow gravity to help keep the cord in the uterus and prevent further descent.
Choice C is wrong because supine position can worsen cord compression and compromise fetal blood flow. Choice D is wrong because lithotomy position can also increase cord descent and reduce fetal perfusion. Choice E is wrong because Sims position can cause cord prolapse if the membranes are intact or rupture spontaneously.
Normal ranges for fetal heart rate are 110 to 160 beats per minute. Cord prolapse can cause fetal bradycardia with decelerations during contractions due to cord compression.
This is a sign of fetal distress and requires immediate intervention.